b^2+3b-10000=0

Solution for b^2+3b-10000=0 equation:

b^2+3b-10000=0

a = 1; b = 3; c = -10000;
Δ = b2-4ac
Δ = 32-4·1·(-10000)
Δ = 40009
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{40009}}{2*1}=\frac{-3-\sqrt{40009}}{2}
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{40009}}{2*1}=\frac{-3+\sqrt{40009}}{2}
$